Binary Insertion sort is a variant of Insertion sorting in which proper location
to insert the selected element is found using the binary search.
Binary search reduces the number of comparisons in order
to find the correct location in the sorted part of data.
In worst case scenario –
Normal insertion sort takes O( i ) time in its ith iteration
whereas using binary search can reduce it to O(log( i )).
Note – Overall time complexity of the algorithm in the worst
case is still O(n2) because of the number of swaps required to put every
element at the correct location.
Implementation
of Binary Insertion Sort in C
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#include
<stdio.h> // A
binary search based function to find the position // where
item should be inserted int
binarySearch(int a[], int item, int low, int high) { if
(high <= low) return
(item > a[low])? (low + 1): low; int
mid = (low + high)/2; if(item
== a[mid]) return
mid+1; if(item
> a[mid]) return
binarySearch(a, item, mid+1, high); return
binarySearch(a, item, low, mid-1); } //
Function to sort an array a[] of size 'n' void
insertionSort(int a[], int n) { int
i, loc, j, k, selected; for
(i = 1; i < n; ++i) { j
= i - 1; selected
= a[i]; //
find location where selected sould be inseretd loc
= binarySearch(a, selected, 0, j); //
Move all elements after location to create space while
(j >= loc) { a[j+1]
= a[j]; j--; } a[j+1]
= selected; } } // Driver
program to test above function int
main() { int
a[] = {4, 10, 3, 1, 9, 15}; int
n = sizeof(a)/sizeof(a[0]), i; insertionSort(a,
n); printf("Sorted
array: \n"); for
(i = 0; i < n; i++) printf("%d
",a[i]); return
0; } |
Output:-
Sorted array - 1 3 4 9 10 15
Implementation
of Binary Insertion Sort in Java
In this implementation, I have used library functions for
binary search and shifting array to one location right.
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package
com.codingeek.algorithms.sorting; import
java.util.Arrays; class
BinaryInsertionSort{ public
static void main(String[] args) { final
int[] input = { 4, 10, 3, 1, 9, 15
}; System.out.println("Before
Sorting - " +
Arrays.toString(input)); new
BinaryInsertionSort().sort(input); System.out.println("After
Sorting - " +
Arrays.toString(input)); } public
void sort(int array[]) { for
(int i = 1; i < array.length; i++) { int
x = array[i]; //
Find location to insert using binary search int
j = Math.abs(Arrays.binarySearch(array, 0,
i, x) + 1); //Shifting
array to one location right System.arraycopy(array,
j, array, j+1, i-j); //Placing
element at its correct location array[j]
= x; } } |
Output:-
Before Sorting - [4, 10, 3, 1, 9, 15]
After Sorting - [1, 3, 4, 9, 10, 15]
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share the wisdom and share this to motivate us to keep writing such online
tutorials for free and do comment if anything is missing or wrong or you need
any kind of help.
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